Thursday, December 31, 2009 :::
I was watching Jeopardy today when I suddenly got curious about what might be the highest possible amount a contestant could win in one game, if they happened to answer every single question correctly, including all the Double and Final Jeopardies (assuming they always bet the maximum). So being the biggest nerd on the planet, I did some math:
Six Categories, six dollar amounts: $200, $400, $600, $800, $1000
$3,000 x 6 = $18,000
One Daily Double, assuming it's in the $200 spot (which it never is) and a player picked that one last: 17,800 x 2 = $35,600
Double Jeopardy Round:
Six Categories, six dollar amounts: $400, $800, $1200, $1600, $2000
$6,000 x 6 = $36,000
Two Daily Doubles, assuming they're in the $400 spots (which they never are) and a player picked them last: $35,200 + $35,600 from first round x 2 = $141,600 x 2 = $283,200
Double it for Final Jeopardy = $566,400
Although it would probably something a tad less than that, because Daily Doubles are generally located in the higher dollar amounts, although I don't know if there's any rule that says they AWLAYS are.
By contrast, it took Ken Jennings over 75 games to win just $3,022,700, which by my calculations, he should have been able to do in 6 if he were really all that smart.
What has this got to do with New Years?
EFF YOU! THAT'S WHAT IT'S GOT TO DO WITH NEW YEARS!
::: posted by dan at 4:35 PM :: [ link ] :: (3) comments
3 previous comments:
Happy New Year, Dan! It looks like your fame is spreading: http://www.fark.com/cgi/comments.pl?IDLink=4891575&tt=voteresults&startid=57082236#c57079964
Word verification: "goness" like wow, man, totally....
By , at 6:19 PM
I have always wondered that, but never bothered to do the math. Figured someone else would. Thanks!
By , at 6:28 PM
No, really. I don't remember how I found you but you make me laugh so hard!!!! Thank you!
By , at 10:31 PM
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